A mass (M) is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period T. If the mass is increased by m, the time period becomes `(5T)/3`. Then the ratio of `m/M` is .

A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period T. If the mass is increased by m, the time period becomes 5T/3. What is the ratio m/M?

A mass .M. is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period .T., if the mass is increased by .m., time period becomes (5t)/(3) , then the ratio of (m/M) is

A mass M is suspended from a spring of negligible mass. The spring is pulled a little then released, so that the mass executes simple harmonic motion of time period T . If the mass is increased by m , the time period becomes (5T)/(3) . Find the ratio of m//M .

A mass M is suspended from a spring of negligible mass. The spring is pulled a little then released, so that the mass executes simple harmonic motion of time period T . If the mass is increased by m , the time period becomes (5T)/(3) . Find the ratio of m//M .