A projectile is projected at an angle `alpha` with an initial velocity u. The time t, at which its horizontal velocity will equal the vertical velocity for the first time

A projectill is projected at an angle (alpha gt 45^(@)) with an initial velocity u. The time t, at which its magnitude of horizontal velocity will equal the magnitude of vertical velocity is :-

A projectill is projected at an angle (alpha gt 45^(@)) with an initial velocity u. The time t, at which its magnitude of horizontal velocity will equal the magnitude of vertical velocity is :-

A projectill is projected at an angle (alpha gt 45^(@)) with an initial velocity u. The time t, at which its magnitude of horizontal velocity will equal the magnitude of vertical velocity is :-

In projectile motion, a body is projected at an angle theta with velocity u then the horizontal component of velocity will be

When a projectile is fired at an angle theta w.r.t horizontal with velocity u, then its vertical component:

A particle is projected in air with an initial velocity u directed at an angle theta above horizontal. After time t_(0) the velocity of the particle is directed at angle phi above horizontal.

A particle of mass m is projected at an angle alpha to the horizontal with an initial velocity u . The work done by gravity during the time it reaches its highest point is