Out of five resistance of `ROmega` each 3 are connected in parallel and are joined to the rest 2 in series. Find the resultant resistance.

Three resistance, each of 1Omega , are joined in parallel. Three such combinations are put in series. The resultant resistance is

The resultant resistance of n wires each of resistance r ohms is R ,when they are connected in parallel.When these n resistances are connected in series,the resultant resistance will be

Four resistances of 16 ohms each are connected in parallel. Four such combinations are connected in series. What is the total resistance?

If 3 resistances of 3 ohm each are connected in parallel, what will be their total resistance?

The resultant resistance of n wires each of resistance r ohms is R, when they are connected in parallel. When these n resistances are connected in series, the resultant resistance will be

Three resistance of one ohm each are connected in parallel. Such connection is again connected with 2//3 Omega resistor in series. The resultant resistance will be

Three resistance , each of 1 ohm are joined in parallel . Three such combinations are put in series , then the resultant resistance will be

With two resistances 2 Omega and 3 Omega In parallel a third resistance of 4 Omega is connected in series.Find their equivalent resistance.