A sinusoidal voltage of peak vale 283V and frequency 50Hz is applied to a series LCR circuit in which `R=3Omega,L=25.48mHandC=786muF`.
Find: Impedance of the circuit.

A sinusoidal voltage of peak vale 283V and frequency 50Hz is applied to a series LCR circuit in which R=3Omega,L=25.48mHandC=786muF . The power factor.

A sinusoidal voltage of peak value 293 V and frequency 50 Hz is applie to a series LCR circuit in which R=6 Omega, L=25 mH and C=750mu F . The impedance of the circuit is

A sinusoidal voltage of peak value 293 V and frequency 50 Hz is applie to a series LCR circuit in which R=6 Omega, L=25 mH and C=750mu F . The impedance of the circuit is

The current through an AC circuit depends on the magnitude of the applied voltage and impedance of the circuit:-A sinusoidal voltage of peak value 283 V and frequency 50 Hz is applied to a series LCR circuit in which R = 3Omega , L =25.48 mH, and C = 796 muF . Find the impedance of the circuit

A sinusoidal voltage of peak value 283 V and frequency 50 Hz is applied to a series LCR circuit in which R=6 Omega , L=50.96 mH and C=398 muF . Find the impedance of the circuit

A sinusoidal voltage of peak vale 283V and frequency 50Hz is applied to a series LCR circuit in which R=3Omega,L=25.48mHandC=786muF . The phase difference between the voltage across the source and the current.

A sinusoidal voltage of peak value 283V and frequency 50 Hz is applied to a series LCR circuit in which R = 3 Omega , L = 25.48 mH and C = 796 muf . Find:-The impedance of the circuit

.A sinusoidal voltage of peak value "283V" and frequency 50Hz is applied to a series LCR circuit in which R=3Omegaa L=25.48mH and C=796 muF .The power factor is