If the temperature of a black body is doubled, the frequency at which the spectral intensity becomes maximum will be

IF the temperature of a black , body is doubled, the wavelength at which the spectral radiancy has its maximum is

Statement I: As the temperature of the black body increases, the wavelength at which the spectral intensity (E_lamda) is maximum decreases. Statement II: The wavelength at which the spectral intensity will be maximum for a black body is proportional to the fourth power of its absolute temperature.

Statement I: As the temperature of the black body increases, the wavelength at which the spectral intensity (E_lamda) is maximum decreases. Statement II: The wavelength at which the spectral intensity will be maximum for a black body is proportional to the fourth power of its absolute temperature.

If the temperature of a black body is increased, then the maximum of the spectrum will

Statement-1 : When temperature of a black body is halved, wavelength corresponding to which energy radiate is maximum become twice. Statement-2 : This is as per Wien's Law.

If the temperature of a black body is increased then the wavelength corresponding to the maximum emission will

Statement-1 : When temperature of a black body is doubled, energy radiated/sec/area becomes 16 times. Statement-2 : This is per Stefan's law.

Statement-1: When the temperature of a black body is doubled from t^(@)C to 2t^(@)C , the radiant power becomes 16 times. Statement-2: The radiant power of a body is proportional to fourth power of absolute temperature.