A spherical charged conductor has surface density of charge as `sigma`. The electric field intensity on its surface is `E`. If the radius of the surface is doubled, keeping `sigma` uncharged, what will be the electric field intensity on the new sphere ?

A spherical charged conductor has sigma as the surface density of charge. The electric field on its surface is E. If the radius of the sphere is doubled keeping the surface density of charge unchanged, what will be the electric field on the surface of the new sphere -

A spherical charged conductor has sigma as the surface charge density. The electricfield on its surface is E. The radius of the sphere is doubled keeping the surface charge density unchanged. Then the electric field on the surface of the new sphere is,

The electric field intensity on the surface of a charged conductor is

The surface density on a copper sphere is sigma . The electric field strength on the surface of the sphere is

The surface density on a copper sphere is sigma . The electric field strength on the surface of the sphere is

The electric field intensity at the surface of a charged conductor is

The surface density on the copper sphere is 'sigma'. The electric field strength on the surface of the sphere is :