If boiling point of an aqueous solution is `100.1^(@)C`. What is its freezing point? Given latent heat of fusion and vaporization of water are `80calg^(-1)` and `540 calg^(-1)` respectively.

If the boiling point of an aqueous solution containing a non-volatile solute is 100.1^(@)C . What is its freezing point? Given latent heat of fusion and vapourization of water 80 cal g^(-1) and 540 cal g^(-1) , respectively.

If the boiling point of an aqueous solution containing a non-volatile solute is 100.15^(@)C . What is its freezing point? Given latent heat of fusion and vapourization of water 80 cal g^(-1) and 540 cal g^(-1) , respectively.

If the boiling point of an aqueous solution containing a non-volatile solute is 100.15^(@)C . What is its freezing point? Given latent heat of fusion and vapourization of water 80 cal g^(-1) and 540 cal g^(-1) , respectively.

If boiling point of an aqueous solution is 100.1^(@)C , its freezing point is ( I_(f) of water =80 cal/g I_(v) of water =540 cal/g)

If the boiling point of an aqueous solution is 100.1^(@)C , what is its freezing point ? Given l_(f)=80 , l_(v)=540 "cal" g^(-1) respectively, of H_(2)O .

If the boiling point of an aqueous solution is 100.1^(@)C , what is its freezing point ? Given l_(f)=80 , l_(v)=540 "cal" g^(-1) respectively, of H_(2)O .

Steam at 100°C is passed into 100 g of ice at 0°C . Finally when 80g ice melts the mass of water present will be [Latent heat of fusion and vaporization are 80 cal g^(-1) and 540 cal g^(-1) respectively, specific heat of water = 1 cal g^(-1) °C^(-1) ]

Steam at 100°C is passed into 100 g of ice at 0°C . Finally when 80g ice melts the mass of water present will be [Latent heat of fusion and vaporazisation are 80 cal g^(-1) and 540 cal g^(-1) respectively, specific heat of water = 1 cal g^(-1) °C^(-1) ]