Let f(x) be a non-negative continuous function such that the area bounded by the curve y=f(x), the x-axis, and the ordinates `x=(pi)/(4) and x=betagt(pi)/(4)" is "beta sin beta +(pi)/(4)cos beta +sqrt(2)beta.` Then `f'((pi)/(2))` is

Let f(x) be a non-negative continuous function such that the area bounded by the curve y=f(x), the x -axis,and the ordinates x=(pi)/(4) and x=beta>(pi)/(4) is beta sin beta+(pi)/(4)cos beta+sqrt(2)beta Then f'((pi)/(2)) is ((pi)/(2)-sqrt(2)-1)( b) ((pi)/(4)+sqrt(2)-1)-(pi)/(2)( d) (1-(pi)/(4)-sqrt(2))

Let f(x) be a non-negative continuous function such that the area bounded by the curve y=f(x) , x-axis and the ordinates x=(pi)/(4) and x = bet gt (pi)/(4) is beta sin beta +(pi)/(4) cos beta +sqrt(2) beta then f((pi)/(2))=

Let f(x) be non- negative continuous function such that the area bounded by the curve y=f(x) , x- axis and the ordinates x= (pi)/(4) and x = beta ( beta gt (pi)/(4)) is beta sin beta + (pi)/(4) cos beta + sqrt(2) beta . Then the value of f((pi)/(2)) is-

Let f(x) be a non-negative continuous function such that the area bounded by the curve y=f(x), x-axis and the ordinates x=pi/4 and x=beta gt pi/4 is : (beta sin beta + pi/4 cos beta +sqrt2beta) . Then f(pi/2) is :

Let f(x) be a non-negative continuous function such that the area bounded by the curve y=f(x), the x-axis, and the ordinates x=pi/4 and x=beta>pi/4 is betasinbeta+pi/4cosbeta+sqrt(2)betadot Then f(pi/2) is

Let f(x) be a non-negative continuous function such that the area bounded by the curve y=f(x), the x-axis, and the ordinates x=pi/4a n dx=beta>pi/4i sbetasinbeta+pi/4cosbeta+sqrt(2)betadot Then f(pi/2) is (pi/2-sqrt(2)-1) (b) (pi/4+sqrt(2)-1) -pi/2 (c) (1-pi/4+sqrt(2))

Let f(x) be a non-negative continuous function such that the area bounded by the curve y=f(x), the x-axis, and the ordinates x=pi/4a n dx=beta>pi/4i sbetasinbeta+pi/4cosbeta+sqrt(2)betadot Then f(pi/2) is (pi/2-sqrt(2)-1) (b) (pi/4+sqrt(2)-1) -pi/2 (c) (1-pi/4+sqrt(2))

Let f be a non-negative continuous function such that the area bounded by the curve y = f(x), x-axis and the coordinates x = 3:sqrt2 and x = beta > pi/4 is (beta sin beta + pi/4 cos beta + sqrt2 beta). then f(pi/2) is: