`z=(1+cos6pi)+isin6pi`

z=cos(pi/6)+isin(pi/6)=?

If z = cos"" pi/4+ isin (pi/6) ,then

((1+cos. pi/8+isin. pi/8)/(1+cos. pi/8- isin. pi/8))^(8)=

The value of [(1+cos(pi/8)+isin(pi/8))/(1+cos(pi/8)-isin(pi/8))]^8 is

If z=cos(pi/4)+isin(pi/6) , then a. |z|=1, arg(z)=\ pi/4 b. |z|=1, arg(z)=\ pi/6 c. |z|=(sqrt(3))/2, arg(z)=(5pi)/(24) d. |z|=(sqrt(3))/2, arg(z)=tan^(-1)(1/sqrt(2))

Represent the quotient (7(cos((3pi)/4)+isin((3pi)/4)))/(21(cos(pi/4)+isin(pi/4)) in polar form.

z=5(cos((7pi)/6)+isin((7pi)/6))=?

(cos(pi/6)+isin(pi/6))^7=?