A ball is projected from the ground at angle `theta` with the horizontal. After `1 s`, it is moving at angle `45^@` with the horizontal and after `2 s` it is moving horizontally. What is the velocity of projection of the ball ?

A ball is projected horizontal from the top of a tower with a velocity v_(0) . It will be moving at an angle of 60^(@) with the horizontal after time.

A ball is projected horizontal from the top of a tower with a velocity v_(0) . It will be moving at an angle of 60^(@) with the horizontal after time.

A shot is fired at an angle theta to the horizontal such that it strikes the hill while moving horizontally. Find the initial angle of projection theta .

A shot is fired at an angle theta to the horizontal such that it strikes the hill while moving horizontally. Find the initial angle of projection theta .

A ball is thrown at an angle theta with the horizontal. Its time of flight is 2 s. Its horizontal range is 100 m. What is the horizontal component of velocity of projection ? Take g =10 ms^(-2) .

A body is projected at an angle of 30^@ with the horizontal and with a speed of 30 ms^-1 . What is the angle with the horizontal after 1.5 s ? (g = 10 ms^-2) .

A body is projected at an angle of 30^@ with the horizontal and with a speed of 30 ms^-1 . What is the angle with the horizontal after 1.5 s ? (g = 10 ms^-2) .

One second after the projection, a stone moves at an angle of 45^@ with the horizontal. Two seconds from the start, it is travelling horizontally. Find the angle of projection with the horizontal. (g=10 ms^(-2)) .

A particle is projected from the ground . One second after the projection, the particle is found to be moving at an angle 45^(@) with the horizontal . Speed of the particle becomes minimum two seconds after the projection . If angle of projection is tan^(-1)(n) , then what is the value of n ?