Home
Class 11
PHYSICS
A ballet dancer is rotating at angular v...

A ballet dancer is rotating at angular velocity `omega` on smooth horizontal floor. The ballet dancer folds his body close to his axis of rotation by which his radius of gyration decreases by `1//4^(th)` of his initial radius of gyration, his final angular velocity is

Promotional Banner

Similar Questions

Explore conceptually related problems

A ballet dancer is rotating about his own vertical axis at an angular velocity 100 rpm on smooth horizontal floor. The ballet dancer folds himself close to his axis of rotation by which is moment of inertia decreases to half of initial moment of inertia then his final angular velocity is

A ballot dancer is rotating about hyis own vertical axis on smooth horizontal floor with a time period 0.5 sec . The dancer flods himself close to his axis of rotation due to which his radius of gyration decreases by 20% , then his new time period is

A ballet dancer is rotating about his own vertical axis. Without external torque if his angular velocity is doubled then his rotational kinetic energy is

A dancer is rotating on smooth horizontal floor with an angular momentum L The dancer folds her hands so that her moment of inertia decreases by 25%. The new angular momentum is

The angular velocity of a body is increased from 5 rad/s to 20 rad/s, without applying a torque but by changing its moment of Inertia. What is the relation between the new radius of gyration and the initial radius of gyration?

A person sitting firmly over a rotating stool has his arms stretched. If he folds his arms, his angular momentum about the axis of rotation

A body of mass M is rotating about an axis with angular velocity omega . If k is radius of gyration of the body about the given axis, its angular momentum is