A body of mass `30 kg` starts running rest along a ciruclar path of radius `6m` with constant tangential acceleration of magnitude `2 m//s^(2)`. After `2 sec` from start he feels that his shoes started slipping on ground. The friction coefficient between his shoes and ground is `: ( ` Take `g=10m//s^(2))`

A bot of mass 30kg starts running from rest along a circular path of radius 6m with constant tangential acceleration of magnitude 2m//s^(2) . After 2sec from start he feels that his shoes started slipping on ground. The friction coefficient between his shoes and ground is mu . Find 2/(mu) . (Take g=10m//s^(2) )

A particle of mass 2kg start motion form rest on a circular path of radius r=4m with constant tangential acceleration 4 ms^(-2) . Find the net work done on the particle in initial 1 second.

A body starts revolving from rest in a circular path of radius 2 m with tangential acceleration a =2tm//s^(2) . If its total acceleration at t=2 sec. is nsqrt(5) m//s^(2) , then the value of n is:

If a particle of mass m start from along curved circular path shown in figure with constant tangential acceleration a, then net force at B on the particle has the magnitude :

A body of mass 1 kg starts moving from rest t = 0 in a circular path of radius 8 m. Its kinetic energy varies with time as k = 2t^(2) J then magnitude of centripetal acceleration ( in m//s^(2) ) at t = 2s is.

A particle is moving on a circular path of radius 1 m with 2 m/s. If speed starts increasing at a rate of 2m//s^(2) , then acceleration of particle is

A particle is moving on a circular path of radius 1 m with 2 m/s. If speed starts increasing at a rate of 2m//s^(2) , then acceleration of particle is

An atheletic completes a circular loop moving with maximum constant speed in 10 sec. what is the radius r (in m) of the loop if friction coefficient between his shoes and ground is 0.8. fill r/10 in OMR sheet. Take pi^(2)=10 .

A lift, initially at rest on the ground, starts ascending with constant acceleration 8m//s^(2) After 0.5 seconds, a bolt falls off the floor of the lift. The velocity of the lift at the instant the bolt hits the ground is m/s .[Take g=10 m//s^(2) ]

A lift, initially at rest on the ground, starts ascending with constant acceleration 8m//s^(2) After 0.5 seconds, a bolt falls off the floor of the lift. The velocity of the lift at the instant the bolt hits the ground is m/s .[Take g=10 m//s^(2) ]