Light of wavelength `lamda` is incident on a slit of width d. the resulting diffraction pattern is observed on a screen at a distance D. the linear width of the principal maximum is, then equal to the width of the slit if D equals

Light of wavelength lamda is incident on a slit width d. The resulting diffraction pattern is observed on a screen at a distance D. The linear width of the principal maximum is then equal to the width of the slit if D equals

Light of wavelength lamda is incident on a slit width d. The resulting diffraction pattern is observed on a screen at a distance D. The linear width of the principal maximum is then equal to the width of the slit if D equals

Light of wavelength lambda is incident on slit of width d. The resulting diffraction pattern is observed on a screen placed at distance D. The linear width of central maximum is equal to width of the slit then D = .......

A light of wavelength lambda falls on a narrow slit of width d.A diffraction fringe is formed on a screen placed at distance D from the slit. If the linear width of the central maximum equals to the width of the slit, will be the value of D?

How does the angular width of principal maximum in the diffraction pattern vary with the width of slit ?

How does the angular width of principal maximum in the diffraction pattern vary with the width of slit ?

Light of wavelength lambda is incident on a slit of width d and distance between screen and slit is D. Then width of maxima and width of slit will be equal if D is

Light of wavelength lambda is incident on a single sht of width. 'a' and the distance between slit and screen is 'a. In diffraction pattern, if slit width is equal to the width of the central maximum then 'O is equal to