A constant torque is acting on a wheel. If starting from rest, the wheel makes n rotations in t seconds, show that the angular
acceleration is given by `alpha = (4pi n)/(t^(2)) rad s^(-2)`.

A constant torque is acting on a wheel. If starting from rest, the wheel makes n rotations in t seconds, Show that the angular acceleration is given by alpha = \frac { 4 \pi n } { t ^ { 2 } } rad s^-2 .

On the application of a constant torque , a wheel is turned from rest through 400 radians in 10 s. The angular acceleration is :

On the application of a constant torque , a wheel is turned from rest through 400 radians in 10 s. The angular acceleration is :

A torque of 50 N-m acting on a wheel at rest rotates it through 200 rad in 5 sec. Its angular acceleration is -

A torque of 100 Nm acting on a wheel at rest, rotates it through 200 radians in 10 s. The angular acceleration of the wheel, in rad//s^(2) is

A wheel starts from rest and acquires an angular velocity of 60 rad//s in half a minute. Then its angular acceleration is

A constant torque acting on a uniform circular wheel changes its angular momentum from A to 4A in 4 second, then the magnitude of the torque is

A wheel starting from rest ia rotating with a constant angular velocity of 3 rad s^-1 . What is its angular acceleration after 4 s?

A wheel starts from rest and acquires an angular velocity of 60 rad//s in half a minute . Then its angular acceleration is