If a disc of mass m and radius R totates with an angular acceleration a, of the torque acting on the disc is

A particle of mass M and radius of gyration K is rotating with angular acceleration alpha . The torque acting on the particle is

A particle of mass M and radius of gyration K is rotating with angular acceleration alpha . The torque acting on the particle is

A particle of mass M and radius of gyration K is rotating with angular acceleration alpha . The torque acting on the particle is

A body of mass 'm' and radius of gyration 'K' is rotating with angular acceleration a. Then the torque acting on the body is

A body of mass 'm' and radius of gyration 'K' is rotating with angular acceleration alpha . Then, the torque acting on the body is:

If a tangential force mg is applied to a disc of mass m and radius r, the angular acceleration produced in it is?

If a tangential force mg is applied to a disc of mass m and radius r, the angular acceleration produced in it is?

Three forces of magnitude F, F and sqrt(2F) are acting on the periphery of a disc of mass m and radius R as shown in the figure. The net torque about the centre of the disc is

A circular disc of mass M and radius R is rotating with angular velocity omega . If two small spheres each of mass m are gently attached to two diametrically opposite points on the edge of the disc, then the new angular velocity of the disc will be

Two equal and opposite forces are allplied tangentially to a uniform disc of mass M and radius R as shown in the figure. If the disc is pivoted at its centre and free to rotate in its plane, the angular acceleration of the disc is :