The ends of a metal rod are kept at temperatures `theta_1` and `theta_2` with `theta_2gttheta_1`. The rate of flow of heat along the rod is directly proportional to

The ends of a metal rod are kept at temperature theta_(1) and theta_(2) with theta_(2) gt theta_(1) . At steady state the rate of flow of heat along the rod is directly proportional to

The ends of a metal rod are kept at temperature theta_(1) and theta_(2) with theta_(2) gt theta_(1) . At steady state the rate of flow of heat along the rod is directly proportional to

Amount of heat conducted through a metal rod is directly proportional to

The two ends of a rod of length x and a uniform cross-sectional area A are kept at two temperatures theta_1 and theta_2 , (theta_1, > theta_2) . The rate of heat transfer (dQ)/dt through the rod in a steady state is given by

Two slabs are of the thicknesses d_(1) and d_(2) . Their thermal conductivities are K_(1) and K_(2) respectively They are in series. The free ends of the combination of these two slabs are kept at temperatures theta_(1) and theta_(2) . Assume theta_(1)gttheta_(2) . The temperature theta of their common junction is

Two different metal rods of the same length have their ends kept at the same temperature theta_(1) , and theta_(2) with theta_(2) gt theta_(1) . If A_(1) and A_(2) are their cross-sectional areas and K_(1) and K_(2) their thermal conductivities, the rate of flow of heat in the two rods will be the same it:

Two rods A and B are of equal length each rod has its end at temperature T_1 and T_2 what is the condition that will erasure equal rates of flow of heat through the rods A and B?