Two rods A and B of different materials but same cross section are joined as in figure. The free end of A is maintained at 100°C and the free end of B is maintained at 0°C. If `l_2=2l_1,K_1=2K_2` and rods are thermally insulated from sides to prevent heat loses then the temperature `theta` of the junction of the two rods is

Two rods A and B of same area of cross-section are joined together end to end The free end of the rod A is kept in melting ice at 300 K and free end of B rod at 400 K. The rods are of the same length. The conductivity of A is 3 times that of B. Calculate the temperature of the junction of the rods.

A cylindrical steel rod of length 0.10 m and thermal conductivity 50 W.m^(-1) K^(-1) is welded end to end to copper rod of thermal conductivity 400 W.m^(-1). K^(-1) and of the same area of cross section but 0.20 m long. The free end of the steel rod is maintained at 100^(@)C and that of the copper and at 0^(@)C . Assuming that the rods are perfectly insulated from the surrounding, the temperature at the junction of the two rods–

Two rods of different materials having differnet lengths and same cross sectional areas are joined end to end in a straight line. The free ends of this compound rod are maintained at different temperatures The temperature gradient in each rod will be .

Two metal rods A and B of equal lengths and equal cross- sectional areas are joined end to end. The coefficients of thermal conductivities of A and B are in ratio 2 : 3 , when the free end of A is maintained at 100^(@)C , free end of B at 0^(@)C , the temperature of the junction is

Five rods of same material and same cross-section are joined as shown. Lengths of rods ab, ad and bc are l, 2l and 3l respectively. Ends a and c are maintained at temperatures 200^(@)C and 0^(@)C respectivelly. If x has the value calculated in the above question. Then temperature of junction b or d is

Two rods of same length and cross section are joined along the length. Thermal conductivities of first and second rod are K_(1) and K_(2) . The temperature of the free ends of the first and seconds rods are maintained at theta_(1) and theta_(2) respectively. The temperature of the common junction is

Two rods of same length and cross section are joined along the length. Thermal conductivities of first and second rod are K_1 and K_2 . The temperature of the free ends of the first and second rods are maintained at θ_1 and θ_2 respectively. The temperature of the common junction is

Cylinder copper rod of length 1m and a cylinder steel rod of length 1.5m are joined together end to end. The cross sectional area of eac rod is 3.14cm . The free ends of steel rod and copper rods are maintained at 0^(@)C and 100^(@)C respectively. The surfaces of rods are thermally insulated. Find the temperature of copper steel junction. (Given thermal conductivity of steel =46J//m-s.^(@)C and the thermal conductivity of copper =386J//m-s.^(@)C )

Two rods of material, x and two of y are connected as shown in the figure. All the rods are indentical in length and cross-sectional area. If the end A is maintained at 80^(@)C and the end D is maintained at 10^(@)C , calculate the temperature of the junctions B and C in the steady state. Thermal conductivity of x is double that of y .

Assume the thermal conductivity of copper is 4 times that of brass.Two rods of copper and brass having the same length and cross section are joined end to end.The free and end of copper is at 0°C and the free end of brass is at 100°C.Calculate the temperature of the junctionof thw two rods at equilibirum.