Let B and C are the points of intersection of the parabola `x=y^(2)` and the circle `y^(2)+(x-2)^(2)=8`. The perimeter (in units) of the triangle OBC, where O is the origin, is

Find the points of intersection of the parabola y^2=8x and the line y=2x.

Let B and C are points of interection of the parabola y=x^(2) and the circle x^(2)+(y-2)^(2)=8. The area of the triangle OBC, where O is the origin, is

Let B and C are points of interection of the parabola y=x^(2) and the circle x^(2)+(y-2)^(2)=8. The area of the triangle OBC, where O is the origin, is

P and Q are the points of intersection of the curves y^(2)=4x and x^(2)+y^(2)=12 . If Delta represents the area of the triangle OPQ, O being the origin, then Delta is equal to (sqrt(2)=1.41) .

The point of intersetion of the tangents to the parabola y^(2)=4x at the points where the circle (x-3)^(2)+y^(2)=9 meets the parabola, other than the origin,is

The number of point of intersection of the circle x^(2)+y^(2)=2ax with the parabola y^(2)=x is

The point of intersection of the tangents to the parabla y^(2)=4x at the points where the circle (x-3)^(2)+y^(2)=9 meets the parabola other than origin is

The point of intersection of the circle x^(2) + y^(2) = 8x and the parabola y^(2) = 4x which lies in the first quadrant is

The locus of the point of intersection of the perpendicular tangents to the circle x^(2)+y^(2)=a^(2), x^(2)+y^(2)=b" is "