A sinusoidal voltage of peak vale 283V and frequency 50Hz is applied to a series LCR circuit in which `R=3Omega,L=25.48mHandC=786muF`.
The power factor.

.A sinusoidal voltage of peak value "283V" and frequency 50Hz is applied to a series LCR circuit in which R=3Omegaa L=25.48mH and C=796 muF .The power factor is

A sinusoidal voltage of peak vale 283V and frequency 50Hz is applied to a series LCR circuit in which R=3Omega,L=25.48mHandC=786muF . The phase difference between the voltage across the source and the current.

A sinusoidal voltage of peak vale 283V and frequency 50Hz is applied to a series LCR circuit in which R=3Omega,L=25.48mHandC=786muF . Find: Impedance of the circuit.

A sinusoidal voltage of peak value 283 V and frequency 50 Hz is applied to a series LCR circuit in which R = 3 Omega. L = 25.48mH . And C = 796mu F . The power factor.

A sinusoidal voltage of peak value 283 V and frequency 50 Hz is applied to a series LCR circuit in which R = 3 Omega. L = 25.48mH . And C = 796mu F . The power dissipated in the circuit

A sinusoidal voltage of peak value 283 V and frequency 50 Hz is applied to a series LCR circuit in which R = 3 Omega. L = 25.48mH . And C = 796mu F . The impedance of the circuit

A sinusoidal voltage of peak value 293 V and frequency 50 Hz is applie to a series LCR circuit in which R=6 Omega, L=25 mH and C=750mu F . The impedance of the circuit is