Calculate the value of acceleration due to gravity at a point a. 5.0 km above the earth's surface and b. 5.0 km below the earth's surface. Radius of earth =6400 km and the value of g at the surface of the earth is 9.80`ms^2`

Calculate the value of acceleration due to gravity at a point .5.0 km below the earth's surface. Radius of earth =6400 km and the value of g at the surface of the earth is 9.8 ms^2

Compare the weight of a body when it is at (a) 80 km above the earth,s surface and (b) 80 km below the earth's surface. Take radius of earth = 6,400 km.

The ratio between the values of acceleration due to gravity at a height 1 //km above and at a depth of 1 km below the Earth’s surface is (radius of Earth is R)

Find the value of g at a height of 400 km above the surface of the earth . Given radius of the earth , R = 6400 km and value of g at the surface of the earth = 9.8 ms^(-2) .

What will be the value of the acceleration due to gravity at a point 3 km above the earth's surface ? Diameter of the earth =12800 km and g=980cm*s^(-2) on the surface of the earth.

What would be the value of acceleration due to gravity at a point 5 km below the earth's surface ? (R_(E) = 6400 km, g_(E) = 9.8 "ms"^(-2))

What would be the value of acceleration due to gravity at a point 5 km below the earth's surface ? (R_(E) = 6400 km, g_(E) = 9.8 "ms"^(-2))

(a) Assuming the earth to be a sphere of uniform density, calculate the value of acceleration due to gravity at a point, 1600 km above the earth, (b) Also find the rate of variation of acceleration due to gravity above the earth's surface. Radius of earth =6400 km, g =9.8 m//s^(2) .

Find the value of acceleration due to gravity in a mine at a depth of 80 km from the surface of the earth . Radius of the earth = 6400 km .