A bar magnet of moment `m = 4.0 Am^(2)` lies on a table horizontally in the earth's magnetic field `H = 30 Am^(-1)`. A student turns it and holds it erect on the table. What is the work done by the student.

A short magnet of moment 6.75 Am^(2) produces a neutal point on its axis. If horizontal component of earth's magnetic field is 5xx10^(-5) "Wb"//m^(2) , then the distance of the neutal point should be

A short magnet of moment 6.75 Am^(2) produces a neutal point on its axis. If horizontal component of earth's magnetic field is 5xx10^(-5) "Wb"//m^(2) , then the distance of the neutal point should be

A magnet of magnetic dipole moment 5.0 Am^(2) is lying in a uniform magnetic field of 7 xx 10^(-4) T such that its dipole moment vector makes an angle of 30° with the field. The work done in increasing this angle from 30° to 45° ls about ......... J.

A bar magnet of magnetic moment 0.4 Am^(2) is placed in a uniform magnetic field of induction 5 xx10^(-2) tesla. What is the torque acting on the magnet if the angle between the magnetic induction and the magnetic moment is 30^(@) .

A bar magnet having a magnetic moment of 2 xx l0 ^4 JT^-1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6 xx 10^-4 T exits in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60^@ from the field is:

A short bar magnet is placed with its north pole pointing north. If magnetic moment of magnet is 0*4Am^2 and horizontal component of earth's magnetic field is 0*4 gauss, what is the distance of neutral point from the centre of the magnet?