A body executing S.H.M. has a period of 3 s under one force and 4 s under another force. Then time period under the action of both the forces together in the same direction is

A body has a time of 3 s under the action of one force and 4 s under the action of another force. Calculate the time period when both the forces act in the same direction simultaneously. Assume that the body undergoes the same displacement, under the action of the two different forces.

A body has a time period (4/5) s under the action of one force and (3/5) s under the action of another force. Then time period when both the forces are acting in the same direction simultaneously will be

A particle under the action of one SHM has a period of 3 s and under the effect of another it has a period 4s. Its time period under the combined action of both the SHM's in the same direction is (0.4x)second. Find value of x?

A particle under the action of one SHM has a period of 3 s and under the effect of another it has a period 4s. Its time period under the combined action of both the SHM's in the same direction is (0.4x)second. Find value of x?

A body has a time period (4/5) s under the action of one force and (3/5) s under the action of another force. Then time period when both the forces are acting in the opposite direction simultaneously will be

A particle has a time period of 1s under the action of a certain force and 2 s under the action of another force. Find the time period when the forces are acting in the same direction simultaneously.

What is net force on a body under the action of a couple ?

A particle under the action of a force has a period of 3s and under the action of another force it has a period 4sec in SHM . What will be its period under the combined action of both forces in the same direction?

A particle under the action of a force has a period of 3s and under the action of another force it has a period 4sec in SHM . What will be its period under the combined action of both forces in the same direction?