one gram of activated carbon has a surface are of `1000m^(2)`. Considering complete coverage as well as monomolecular adsorption , how much ammonia at 1 atm and 273 K would be absorbed on the surface of `44/7` g carbon if radius of a ammonia molecules is `10^(-8) cm`.

One gram of activated carbon has a surface area of 1000 m. Considering complete coverage as well as monomolecular adsorption, how much ammonia at 1 atm and 273 K would be adsorbed on the surface of (44)/(7) g carbon if radius of a ammonia molecules is 10^(-8) cm . "[Given , " N_A = 6 xx 10^(23)]

One gram of activated carbon has a surface area of 1000cm^2 considering complete coverage as well as monomolecular adsorption. How much ammonia at latm and 273K would be adsorbed on the surface of 44/7gr. carbon. If radius of a ammonia molecule is 10^(-8)cm .........

The surface are of activated charcoal is 10^(3)m^(3)g^(-1) .If effective surface area of ammonia molecule is 0.129nm^(2) and complete monolayer coverage is assumed. how much ammonia at STP could be adsorbed on 10g of charcoal?

The volume of nitrogen gas Vm (at STP) reqired to cover a sample of silica gel with a monomolecular layer is 129cm^(3)g^(-1) of gel. Calculate the surface area per gram of the gel if each nitrogen molecule occupies 16.23xx10^(-20)m^(2) .

The volume of nitrogen gas Vm (at STP) reqired to cover a sample of silica gel with a monomolecular layer is 129cm^(3)g^(-1) of gel. Calculate the surface area per gram of the gel if each nitrogen molecule occupies 16.23xx10^(-20)m^(2) .

1 L of 0.6 M acetic acid is shaken with 2 g activated carbon.Activated carbon absorbs some acetic acid on its surface only.This process is called adsorption.The final concentration of the solution after adsorption is 0.5 M.What is the amount of acetic acid absorbed per gram of carbon.