A lead bullet of mass 21 g travelling at a speed of `100m//s` comes to rest in a wooden block . If no heat is taken away by the wood , the rise in temperature of the bullet in the wood nearly is (specified heat of lead =`30 cal//kg^(@)C` )

A lead bullet of mass 21g travelling at a speed of 100 ms^(-1) comes to rest in a wooden block. If no heat is taken away by the wood, the rise in temperature of the bullet in the wood nearly is (Sp. Heat of lead 80cal/kg .^(@)C )

A lead bullet of mass 10 g travelling at 300 m//s strikes against a block of wood and comes to rest. Assuming 50% of heat is absorbed by the bullet, the increase in its temperature is (Specific heat of lead = 150 J//kg^(@)C )

A lead bullet weighing 20 g and moving with a velocity of 100 ms^(-1) comes to rest in a fixed block of wood. Calculate the heat developed and the rise in temperature of the bullet assuming that the half of the heat is absorbed by the bulley. The specific heat of lead is 0.03 cal g^(-1).^(@)C^(-1) .

A bullet of mass 10 g travelling horizontally with a velocity of 150 m s^-1 strikes a stationary wooden block and comes to rest in 0.03 s. Calculate the distance of penetration of the bullet into the block.

A lead bullet of 10g travelling at 300m//s strikes against a block of wood and comes to rest. Assuming 50% heat is absorbed by the bullet, the increase in its temperature is (sp-heat of lead is 150J//Kg-K )

A lead bullet of 10g travelling at 300m//s strikes against a block of wood and comes to rest. Assuming 50% heat is absorbed by the bullet, the increase in its temperature is (sp-heat of lead is 150J//Kg-K )

A bullet of mass 10 g travelling horizontally with a velocity of 150 m s^-1 strikes a stationary wooden block and comes to rest in 0.03 s. Calculate the force exerted by the wooden block

A bullet of mass 0.03 kg moving with a speed of 400m/s penerates 12 cm into fixed block of wood. Calculate the average force exerted by the wood on the bullet.