What is the energy stored per unit volume in a copper wire of uniform cross section and length 1.5 m, when it is stretched to a length of 1.51 m by a stress of `3 xx 10^(2) N//m^(2)` ?

Find the energy stored per unit volume of a steel wire of length 1m when it is stretched by 0.2mm. Given Y for steel = 2.1 x 10^11 N/m^2

When a force is applied on a wire of uniform cross-sectional area 3xx10^-6m^2 and length 4 m, the increase in length is 1mm. Energy stored in it will be (Y=2xx10^(11)(N)/(m^2) )

When a force is applied on a wire of uniform cross-sectional area 3xx10^-6m^2 and length 4 m, the increase in length is 1mm. Energy stored in it will be (Y=2xx10^(11)(N)/(m^2) )

When a force is applied on a wire of uniform cross-sectional area 3×10 −6 m 2 and length 4m, the increase in length is 1 mm. Energy stored in it will be (Y=2×10 11 N/m 2 )

When a force is applied on a wire of uniform cross-sectional are 3 xx 10^(-6) m^(2) and length 4 m, the increase in length is 1 mm. Energy stored in it will be (Given, Y = 2 xx 10^(11) Nm^(-2) )

The energy stored per unit volume in copper wire, which produces longitudinal strain of 0.1% is (Y = 1.1 xx 10^(11) N//m^(2))

The energy stored per unit volume in copper wire, which produces longitudinal strain of 0.1% is (Y = 1.1 xx 10^(11) N//m^(2))

Calculate the amount of work done for a wire which area of cross section 10^-6m^2 and length 1.5m to increase the length 4 xx 10^-3 m. Young's modules of elasticity 2 xx 10^(11N//m^2) .