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State the reason for the following : (...

State the reason for the following :
(i) Cu (I) ion is not stable in an aqueous solution.
(ii) Unlike `Cr^(3+),Mn^(2+),Fe^(3+)` and the subsequent other `M^(2+)` ions of the 3d series, the 4d and 5d series metals generally do not form stable oxidation states.

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State reasons for the following: (i) Cu(I) ion is not stable in an aqueous solution. (ii) Unlike Cr^(3+)Mn^(2+), Fe^(3+) and the subsequent other M2+ ions of the 3d series of elements, the 4d and the 5d series metals generally do not form stable cationic species.

Complete the following chemical equation: (i) MnO_(4)^(-)(aq)+s_(2)O_(3)^(2-)(aq)+H_(2)O(I) to (ii) MnO_(4)^(-) +NO_(2)^(-)+H^(+) to State reason for the following : (i) Cu(I) ion is not stable in an aqueous solution. (ii) Unlike Cr^(3+),Mn^(2+),Fe^(3+) and the subsequently other M^(2+) ions of the 3d series of elements, the 4d and the 5d series metals generally do not form stable cationic species.

Complete the following chemical equation: (i) MnO_(4)^(-)(aq)+s_(2)O_(3)^(2-)(aq)+H_(2)O(I) to (ii) MnO_(4)^(-) +NO_(2)^(-)+H^(+) to State reason for the following : (i) Cu(I) ion is not stable in an aqueous solution. (ii) Unlike Cr^(3+),Mn^(2+),Fe^(3+) and the subsequently other M^(2+) ions of the 3d series of elements, the 4d and the 5d series metals generally do not form stable cationic species.

Unlike Cr^(3+), Mn^(2+), Fe^(3+) and the subsequent M^(3+) ions of 3d series of elements, the 4d and 5d series metals generally do not form stable cationic species. Explain.

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Account for the following: (i) Cu^(+) ions are not stable in aqueous solution. (ii) Most of the transition metal ions exhibit paramagnetic behaviour.

Assertion : Cu^+ ion is not stable in aqueous solution. Reason : Cu^+ contains 3d-filled subshell.

In 3d series , Mn shows highest oxidation state . Why ?