`E^(o)` for the reaction `Fe + Zn^(2+) rarr Zn + Fe^(2+)` is `– 0.35` V. The given cell reaction is :

E^(0) for the reaction Fe + Zn^(2+) to Zn + Fe^(2+) is -0.35 V . The given cell reaction is

E^@ for the reaction Fe+Zn^(2+)=Zn+Fe^(2+) is -0.35 V. The given cell reaction is

In the reaction : Zn + FeSO_4 rarr Zn SO_4 + Fe

The standard oxidation potentials, E^(@) , for the half reactions are as, Zn rarr Zn^(2+) + 2e^(-), " " E^(@) = + 0.76 volt Fe rarr Fe^(2+) + 2e^(-), " " E^(@) = +0.41 volt The emf of the cell, Fe^(2+) + Zn rarr Zn^(2+) + Fe is:

The standard potential (E^(0)) for the half reaction are as Zn to Zn^(2+) + 2e^(-) , E^(0) = + 0.76 V Fe to Fe^(2+) + 2e^(-) , E^(0) = + 0.41 V . The emf for the cell reaction Fe^(2+) + Zn to Zn^(2+) + Fe is

The standard oxidation potential, E^(@) , for the reactions are given as: Zn rightarrow Zn^(2+) + 2e^(-) , E^(@) = +0.76V Fe rightarrow Fe^(2+) + 2e^(-) , E^(@) = +0.41V The emf for the cell : Fe^(2+) + Zn rightarrow Zn^(2+) + Fe