The displacement of a particle is given by
`x=a_(0)+(a_(1)t)/(3)-(a_(2)t^(2))/(2)`
where `a_(0),a_(1)` and `a_(2)` are constants. What is its acceleration ?

the displacement of particle is given by X= a_(0) + (a_(1)t)/(2)-(a_(2)t^(2))/(3) . What is its acceleration?

Find the derivative with respect to t, of the function x=A_(0)+A_(1)t+A_(2)t^(2) where A_(0),A_(1)andA_(2) are constants.

The displacement x of a particle along a straight line at time t is given by : x = a_(0) + (a_(1) t)/(2) + (a_(2))/(3) t^(2) . The acceleration of the particle is

The displacement x of a particle along a straight line at time t is given by x = a_(0) +a_(1)t + a_(2)t ^(2) . The acceleration of the particle is

The displacement x of a particle along a straight line at time t is given by x = a_(0) +a_(1)t + a_(2)t ^(2) . The acceleration of the particle is

The displacement x of a particle along a straight line at time t is given by x = a_(0) - a_(1) t + a_(2) t^(2) . The acceleration of the particle is -

The displacement 'x' of a particle moving along a straight line at time t is given by x=a_(0)+a_(1)t+a_(2)t^(2) . The acceleration of the particle is :-

The displacement 'x' of a particle moving along a straight line at time t is given by x=a_(0)+a_(1)t+a_(2)t^(2) . The acceleration of the particle is :-