A metal rod of length L is placed normal to a magnetic field and rotated through one end of rod in circular path with frequency f. The potential difference between it ends will be-

A metal rod of length l is placed normal to a uniform magnetic field B. The rod moves with velocity v perpendicular to the field. Show that motional emf across its ends is Blv.

A conducting rod of length l is hinged at point O. It is a free to rotate in a verical plane. There exists a uniform magnetic field B in horizontal direction. The rod is released from the position shown. The potential difference between the two ends of the rod is proportional to

A conducting rod of length l is hinged at point O. It is a free to rotate in a verical plane. There exists a uniform magnetic field B in horizontal direction. The rod is released from the position shown. The potential difference between the two ends of the rod is proportional to

A rod of length 20 cm is rotating with angular speed of 100 rps in a magnetic field of strength 0.5 T about it’s one end . What is the potential difference betweet two ends of the rod :

A rod of length 20 cm is rotating with angular speed of 100 rps in a magnetic field of strength 0.5 T about it’s one end . What is the potential difference betweet two ends of the rod :

A conducing rod of length l is falling with a velocity v perpendicular to a unifrorm horizontal magnetic field B . The potential difference between its two ends will be