P vs V graph is plotted for 1 mole of hypothetical gas. Range of a/b for this gas in (atm-L/mole). `[R = 0.08 "atm-litre"//-"mle"-K]`

Z us P graph is plotted for 1 mole of hypothetical gas. Volume of gas at this point A is: [R = 0.08 atm L//"mole"-K]

Consider the given graph: Graph is plotted for 1 mol of gas at 400K, find slope of curve [take: R = 0.08(L-atm)/(mol-K)]

For a fixed amount of real gas when a graph of z v//s p was plotted than at very high pressure slope was observed to be 0.01 atm^(-1) . At the same temperature if a graph is plotted b//w pv v//s P then for 2 moles of the gas 'Y' intercept is found to be 40 atm-litre. calculate excluded volume in litres for 20 moles of the real gas.

For a fixed amount of a real gas when a graph of Z us P was plotted then at very high pressure slope was observed to be 0.01 atm^(-1) . At the same temperature if a graph is plotted between PV us P then for 2 moles of the gas the y intercept is found to be 40 atm-litre. Calculate excluded volume in litres for 20 moles of the real gas/

Volume of 1.5 mole of a gas at 1 atm. pressure and 273K is

Kinetic energy of 0.30 moles of He gas in a container of maximum capacity of 4 litres at 5 atmosphere, must be (R = 0.0821 atm litre "mole"^(-1) K^(-1) )________ xx 10^(1) atm.lit

Kinetic energy of 0.30 moles of He gas in a container of maximum capacity of 4 litres at 5 atmosphere, must be (R = 0.0821 atm litre "mole"^(-1) K^(-1) ) ________ xx 10^(1) atm.lit