Formula for degree of hydrolysis ‘h’, h `=[10^(-7)(K_aK_b)^(-1/2)]` is applicable to the salt –

Calculate the degree of hydrolysis of 0*2 (M) sodium acetate solution. (Hydrolysis constant of sodium acetate = 5*6 xx 10^(-10) and ionic product of H_2O = 10^(-14) at 25^@C) "" ^(**"**)

The degree of hydrolysis of 0.01 M NH_(4)CI is (K_(h) = 2.5 xx 10^(-9))

The degree of hydrolysis of 0.01 M NH_(4)CI is (K_(h) = 2.5 xx 10^(-9))

Four solution of NH_(4)Cl are taken with concentration 1M,0.1M,0.01M & 0.001M . Their degree of hydrolysis are h_(1),h_(2) & h_(3),h_(4) . What is the gradation of degree of hydrolysis

Four solution of NH_(4)Cl are taken with concentration 1M,0.1M,0.01M & 0.001M . Their degree of hydrolysis are h_(1),h_(2) & h_(3),h_(4) . What is the graduation of degree of hydrolysis ?

Calculate the hydrolysis constant (K_(h)) and degree of hydrloysis (h) of NH_(4)C1 in 0.1M solution. K_(b) = 2.0 xx 10^(-5) . Calculate the [overset(Theta)OH] ions in the solution.

Calculate the hydrolysis constant (K_(h)) and degree of hydrloysis (h) of NH_(4)C1 in 0.1M solution. K_(b) = 2.0 xx 10^(-5) . Calculate the [overset(Theta)OH] ions in the solution.

The general molecular formula C_(n)H_(2)O_(2) is applicable to