If the curve `y=a^x` and `y=b^x` intersect at angle `alpha`, then `tan alpha=`

If the curves y= a^(x) and y=e^(x) intersect at angle alpha, " then " tan alpha equals: a) |(loga-1)/(loga+1)| b) |(loga+1)/(loga-1)| c) |(loga-1)/(loga)| d) |(loga)/(loga+1)|

If the curves y= a^(x) and y=e^(x) intersect at and angle alpha, " then " tan alpha equals

If the curves y= a^(x) and y=e^(x) intersect at and angle alpha, " then " tan alpha equals

If the curves y= a^(x) and y= b^(x) intersect at an angle alpha , then the value of tan alpha is-

The two curves y=3^x and y=5^x intersect at an angle

The two curves y=3^x and y=5^x intersect at an angle

Show that the curves y = a^x and y = b^x , a gt b gt 0 intersect at an angle of tan^-1 (|(log(a/b)/(1+log a logb))|)

At the point of intersection of the curves y^2=4ax" and "xy=c^2 , the tangents to the two curves make angles alpha" and "beta respectively with x-axis. Then tan alpha cot beta=