Impedence of `L-R Circuit is `100ohm` and phase difference between source voltage and source current is `45^@` of frequency of source `1000Hz` then find inductance of coil.

Impedence of L-R circuit is 100 ohm and phase difference between source voltage and source current is 45^@ of frequency of source 1000Hz then find inductance of coil.

An inductor and a bulb are connected in series to an AC source of 220V, 50Hz. 7C A current of 11A flows in the circuit and phase angle between voltage and current is (pi)/(4) radians. Calculate the impedance and inductance of the circuit

An inductance coil has a impedance of 100 ohm. When a.c. signal of frequency 1,000 hz is applied to the coil, the applied voltage leads the current by 45^@ . Calculate the self inductance of the coil.

An inductor (L) and resistance (R) are connected in series with an AC source. The phase difference between voltage (V) and current (i) is 45^(@) . Now a capacitor (C) is connected in series with L-R, If the phase difference between V and i remain same, then capacitive reactance and impedance of L-C-R circuit will be-

A series RL circuit is connected to an AC power supply of 120 V . The frequency of source is 50 Hz. Calculate the phase difference between the current and voltage in the circuit if values of R and L are 10 Omega and 0.01 H, respectively. Also find the current in the circuit .

An L-C-R circuit is connected to a source of A.C. current. At resonance, the phase difference between the applied voltage and the current in the circuit, is