The capacity of a condenser A is `10muF` and it is charged to a battery of 100 volt. The battery is disconnected and the condenser A is connected to a condenser B the common potential is 40V. The capacity of B is

A condenser of capacity 8 mu F is charged to a potential of 1000 V, calculate the energy stored in the condenser.

A condenser of capacitance 10 muF has been charged to 100V . It is now connected to another uncharged condenser in parallel. The common potential becomes 40 V . The capacitance of another condenser is

A condenser of capacitance 10 muF has been charged to 100V . It is now connected to another uncharged condenser in parallel. The common potential becomes 40 V . The capacitance of another condenser is

A parallel plate air condenser of capacity 10 mu F is charged to a potential of 1000V. The energy of the condenser is

A capcitor of capacitance (1)/(300) muF is connected to a battery of 300V and charged. Then the energy stored in the condenser is

A condenser of capacity 16 mF charged to a potential of 20 V is connected to a condenser of capacity C charged to a potential of 10 V as shown in the figure. If the common potential is 14 V. the capacity C is equal to