2x-3y+1=0
x+4y+3=0

solve for x and y 2x-3y+7=0 3x+4y-5=0

Let (2,3) be the focus of a parabola and x + y = 0 and x-y= 0 be its two tangents. Then equation of its directrix will be (a) 2x - 3y = 0 (b) 3x +4y = 0 (c) x +y = 5 (d) 12x -5y +1 = 0

2x + 3y = 0 , 3 x + 4y = 5 .

2x+3y=0 3x+4y=5

The equations of the sides BC,CA and AB of the ABC are 2x+y+1=0,2x+3y+1=0 and 3x+4y+3=0 respectively.Find the equation of the perpendicular drawn from A on the side BC.

The equations of the sides BC , CA and AB of the DeltaABC are 2x+y+1=0,2x+3y+1=0 and3x+4y+3=0 respectively. Find the equation of the perpendicular drawn from A on the side BC.

Solve for x and y - 2x+3y-8=0 3x+4y-5=0

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then