Home
Class 12
MATHS
Without change of axes the origin is shi...

Without change of axes the origin is shifted to (h, k), then from the equation `x^(2)+y^(2)-4x+6y-7=0`, then therm containing linear powers are missing, then point (h, k) is

Promotional Banner

Similar Questions

Explore conceptually related problems

Without change of axes the origin is shifted to (h, k), then from the equation x^(2)+y^(2)-4x+6y-7=0 , then term containing linear powers are missing, then point (h, k) is

Without change of axes the origin is shifted to (h, k), then from the equation x^(2)+y^(2)-4x+6y-7=0 , the term containing linear powers are missing, then point (h, k) is

Without change of axes the origin is shifted to (h, k), then from the equation x^(2)+y^(2)-4x+6y-7=0 , the term containing linear powers are missing, then point (h, k) is

When the origin is shifted to (2,3) then the original equation of x^(2)+y^(2)+4x+6y+12=0 is

The origin shifted to (-5,3) then the equation y^(2)-12x+6y+69=0 changes as y^(2)=4ax then a

Without changing the direction of the axes, the origin is transferred to the point (2,3). Then the equation x^(2)+y^(2)-4x-6y+9=0 changes to

Without changing the direction of the axes, the origin is transferred to the point (2,3). Then the equation x^(2)+y^(2)-4x-6y+9=0 changes to

The origin is shifted to (1,2), the equation y^(2)-8x-4y+12=0 changes to Y^(2)+4aX=0 then a=

Origin is shifted to (1,2) then the equation y^(2)-8x-4y+12-0 changes as y^(2)=4ax .Then a=