In the spectrum of singly ionized helium , the wavelength of a line abserved is almost the same as the first line of Balmer series of hydrogen . It is due to transition of electron

Calculate the wavelength of the first line in the Balmer series of hydrogen spectrum

Calculate the wavelength of the first line in the Balmer series of hydrogen spectrum.

what is the maximum wavelength of line of balmer series of hydrogen spectrum?

Calculate the wavelength of the first line in the balmer series of hydrogen spectrum

Calculate the wavelength of the first and the last line in the Balmer series of the hydrogen spectrum.

In hydrogen spectrum L_(alpha) line arises due to transition of electron from the orbit n=3 to the orbit n=2. In the spectrum of singly ionized helium there is a line having the same wavelength as that of the L_(alpha) line. This is due to the transition of electron from the orbit:

In hydrogen spectrum L_(alpha) line arises due to transition of electron from the orbit n=3 to the orbit n=2. In the spectrum of singly ionized helium there is a line having the same wavelength as that of the L_(alpha) line. This is due to the transition of electron from the orbit:

Calculate the wavelength of the first and the last line in the Balmer series of hydrogen spectrum?

Calculate the wavelength of the first and the last line in the Balmer series of hydrogen spectrum?

The third line of the Balmer series, in the emission spectrum of the hydrogen atom, is due to the transition from the