If z=x+iy, where `i=sqrt(-1)`, then the equation `abs(((2z-i)/(z+i)))=m` represents a circle, then m can be

If z=x+iy, where i=sqrt(-1) , then the equation abs(((2z-i)/(z+1)))=m represents a circle, then m can be

If z=x+iy, where i=sqrt(-1) , then the equation abs(((2z-i)/(z+1)))=m represents a circle, then m can be

If z=x+iy, then he equation |(2z-i)/(z+1)|=m represents a circle,then m can be (1)/(2) b.1 c.2d.3

If z=x+i y , then he equation |(2z-i)/(z+1)|=m represents a circle, then m can be (a) 1/2 b. 1 c. 2 d. 3

If z=x+i y , then the equation |(2z-i)/(z+1)|=m does not represents a circle, when m is (a) 1/2 (b). 1 (c). 2 (d). 3

If z=x+i y , then the equation |(2z-i)/(z+1)|=m does not represents a circle, when m is (a) 1/2 (b). 1 (c). 2 (d). 3

If z=i^(i^(i)) where i=sqrt-1 then |z| is equal to

If z=i^(i^(i)) where i=sqrt-1 then |z| is equal to

The equation |((1+i)z-2)/((1+i)z+4)|=k does not represent a circle when k is

The equation |z-i|=|z-1|,i=sqrt(-1) represents: