If `z^(3)+(3+2i)z+(-1+ia)=0, " where " i=sqrt(-1)`, has one real root, the value of a lies in the interval (a `in` R)

If z^3+(3+2i)z+(-1+i a)=0 has one real roots, then the value of a lies in the interval (a in R)

If z^3+(3+2i)z+(-1+i a)=0 has one real root, then the value of a lies in the interval (a in R) a.(-2,1) b. (-1,0) c. (0,1) d. (-2,3)

If z^3+(3+2i)z+(-1+i a)=0 has one real roots, then the value of a lies in the interval (a in R) (-2,1) b. (-1,0) c. (0,1) d. (-2,3)

If z^3+(3+2i)z+(-1+i a)=0 has one real root, then the value of a lies in the interval (a in R) a. (-2,1) b. (-1,0) c. (0,1) d. (-2,3)

If z^(3)+3+2i(z+(-1+ia)=0 has on ereal roots,then the value of a lies in the interval (a in R)(-2,1) b.(-1,0) c.(0,1) d.(-2,3)

If 8iz^(3)+12z^(2)-18z+27i=0, (where i=sqrt(-1)) then

If the equation z^(3)+(3+i)z^(2)-3z-(m+i)=0, " where " i=sqrt(-1) " and " m in R , has atleast one real root, value of m is

If the equation z^(3)+(3+i)z^(2)-3z-(m+i)=0, " where " i=sqrt(-1) " and " m in R , has atleast one real root, value of m is

If the equation z^(3)+(3+i)z^(2)-3z-(m+i)=0, " where " i=sqrt(-1) " and " m in R , has atleast one real root, value of m is

The equation z^(2)-i|z-1|^(2)=0, where i=sqrt(-1), has.