यदि सरल रेखा `2x+3y+4+k(6x-y+12)=0` y-अक्ष के समान्तर हो, तो k=..........

The value of k for which the graph of (k- 1)x+ y-2= 0 and (2-k)x-3y+ 1) =0 are parallel is k का मान जिसके लिए (k- 1)x+ y-2= 0 और (2-k)x-3y+ 1) =0 के ग्राफ समांतर हो, है-

{:(2x + (k - 2)y = k),(6x + (2k - 1) y = 2k + 5):}

Find k if the following pairs of circles are orthogonal. x^2 + y^2 - 6x - 8y + 12 = 0 , x^2 + y^2 - 4x + 6y + k = 0

If perpendicular distance between lines 3x + 4y + 10 = 0 and 6x + 8y + k = 0 is 7/2 unit then k = ........

kx + 3y = 3, 12 x + k y = 6 .

3x - y - 5 = 0 , 6x - 2y + k = 0 ( k ne 0 )

यदि (x/3+1,y-2/3) = (5/3,1/3) हो, तो x और y का माना ज्ञात , कीजिये।

The value of k such that the line 2x+3y+4+k(6x-y+12)=0 is perpendicular to the line 7x+5y=c is