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The value of Lambda(eq)^(oo) for NH(4)Cl...

The value of `Lambda_(eq)^(oo)` for `NH_(4)Cl, NaOH` and `NaCl` are `149.74, 248.1` and `126.4 Omega^(-1) cm^(2)" equiv"^(-1)`. The value of `Lambda_(eq)^(oo)` of `NH_(4)OH` is

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The value of Lambda_(eq) ^(oo) for NH_(4) Cl NaOH and NaCl are respectively, 149.74, 248.1 and 126.4 Omega^(-1) cm^(2) "equiv"^(-1) . The value of Lambda_(eq)^(oo) of NH_(4) OH is

The values of wedge_(m)^(oo) for NH_(4)Cl,NaOH, and NaCl are, respectively, 149.74,248.1 ,and 126.4 ohm^(-1)cm^(2)eq^(-1) . The value of wedge_(eq)^(oo)NH_(4)OH is

The values of wedge_(m)^(oo) for NH_(4)Cl,NaOH, and NaCl are, respectively, 149.74,248.1 ,and 126.4 ohm^(-1)cm^(2)eq^(-1) . The value of wedge_(eq)^(oo)NH_(4)OH is

The values of wedge_(m)^(oo) for NH_(4)Cl,NaOH, and NaCl are, respectively, 149.74,248.1 ,and 126.4 ohm^(-1)cm^(2)eq^(-1) . The value of wedge_(eq)^(oo)NH_(4)OH is

The values of equivalent conductivity at infinite dilutions for NH_4Cl , NaOH and NaCl are respectively 149.74, 248.1 and 126.4 "ohm"^(-1) cm^(2) "equi"^(-1) . The value of lambda_(eg)^(oo) of NH_4OH is

Lambda_(m)^(@) for NH_(4)Cl, NaOH and NaCl are 130, 248 and 126.5 "ohm"^(-1)cm^(2)"mol"^(-1) respectively. The Lambda_(m)^(@) of NH_(4)OH will be,

The value of mu^(prop) for NH_(4)Cl, NaOH and NaCl are 129.8, 248.1 and 126.4 ohm^(-1) cm^(2) mol^(-1) respectively. Calculate mu^(prop) for NH_(4)OH solution.