What is the moment of inertia of a uniform circular ring about its diameters ?

What is the moment of inertia of a circular disc about one of its diameters ?

Define theorem of perpendicular axes and apply it to find the moment of inertia of a thin uniform circular ring about any diameter.

The moment of inertia of a uniform circular disc about its diameter is 100 "g cm"^(2) . What is its moment of inertia (i) about its tangent (ii) about an axis perpendicular to its plane ?

State parallel -axes theorem of moment of inertia. The moment of inertia of a circular ring about its diameter is (1)/(2) MR^(2) . Calculate the moment of inertia of the ring about its tangent lying in its plane.

The moment of inertia of a uniform cicrular disc about its diameter is 200g cm^(2) . Its moment of inertia about an axis passing through its centre and perpendicular to its circular face is

The moment of inertia of a uniform cicrular disc about its diameter is 200g cm^(2) . Its moment of inertia about an axis passing through its centre and perpendicular to its circular face is

The moment of inertia of a uniform cicrular disc about its diameter is 200g cm^(2) . Its moment of inertia about an axis passing through its centre and perpendicular to its circular face is

The moment of inertia of semicircular ring about its centre is

What is the moment of inertia of a (i) uniform circular ring of mass 2 kg about its 4 m diameter ? (ii) a thin disc about an axis coinciding with a diameter ?

What is the moment of inertia of a (i) uniform circular ring of mass 2 kg about its 4 m diameter ? (ii) a thin disc about an axis coinciding with a diameter ?