The origin is shifted to `(1,2),` the equation `y^2-8x-4y+12=0` changes to `Y^2+4aX=0` then `a=`

The origin is shifted to (1,2). The equation y^(2) - 8x-4y+12=0 changes to y^(2) = 4ax then a=

Origin is shifted to (1,2) then the equation y^(2)-8x-4y+12-0 changes as y^(2)=4ax .Then a=

By shifting origin to (-1,2) the equation y^(2)+8x-4y+12=0 changes as Y^(2)=4aX then a=

By shifting origin to (-1,2) the equation y^2+8x - 4y + 12 = 0 changes as Y^2 = 4aX then a=

The origin shifted to (-5,3) then the equation y^(2)-12x+6y+69=0 changes as y^(2)=4ax then a

By shifting origin to (-1, 2), the equation y^(2) + 8x - 4y + 12 = 0 changes as y^(2) = 4ax then a =

If by shifting the origin to (1,2) the equation of the parabola y^(2)-4y+8x-4=0 becomes y^(2)=4ax, then a equal to

The coordinates of the point where origin is shifted is (-1,2) so that the equation 2x^(2)+y^(2)-4x+4y=0 become?