An object is projected with a velocity of `20 ms^(-1)` making an angle of `45^(@)` with horizontal. The equation for the trajectory is `h = Ax -Bx^2`, where h is height, x is horizontal distance A and B are constants. The ratio A : B is `(g = 10 ms^-2)`

An object is projected with a velocity of 20(m)/(s) making an angle of 45^@ with horizontal. The equation for the trajectory is h=Ax-Bx^2 where h is height, x is horizontal distance, A and B are constants. The ratio A:B is (g =ms^-2)

An object is projected with a velocity of 20(m)/(s) making an angle of 45^@ with horizontal. The equation for the trajectory is h=Ax-Bx^2 where h is height, x is horizontal distance, A and B are constants. The ratio A:B is (g =ms^-2)

An object is projected with a velocity of 20(m)/(s) making an angle of 45^@ with horizontal. The equation for the trajectory is h=Ax-Bx^2 where h is height, x is horizontal distance, A and B are constants. The ratio A:B is (g =ms^-2)

An object is projected with a velocitiy of 20m//s making an angle of 45^(@) with horizontal. The equation for trajectory is h=Ax-Bx^(2) where h is height x is horizontal distance. A and B are constants. The ratio A.B is x/0.1 . Find value of x.(g=10m//s^(2))