`(x^a/x^b)^(a+b)*(x^b/x^c)^(b+c)*(x^c/x^a)^(c+a)=?` a. `0` b. `x^(abc)` c. `x^(a+b+c)` d. `1`

((x^(a))/(x^(b)))^(a+b-c)*((x^(b))/(x^(c)))^(b+c-a)*((x^(c))/(x^(a)))^(c+a-b)= a.1 b.x^(abc) c.x^(ab+bc+ca) d.x^(a+b+c)

Simplify: (x^(a)/x^(b))^(a+b). (x^(b)/x^(c ))^(b+c) .(x^( c)/x^(a))^(c+a)

If f(x)=((x^2)/(x^b))^(a+b)*((x^b)/(x^c))^(b+c)*((x^c)/(x^a))^(c+a) , then f^(prime)(x) is equal to: (a) 1 (b) 0 (c) x^(a+b+c) (d) None of these

If f(x)=((x^(2))/(x^(b)))^(a+b)*((x^(b))/(x^(c)))^(b+c)*((x^(c))/(x^(a)))^(c+a), then f'(x) is equal to: (a) 1(b)0(c)x^(a+b+c) (d) None of these

(x^(b)/(x^(c)))^(a)xx(x^(c)/(x^(a)))^(b)xx(x^(a)/(x^(b)))^(c)=1

Differentiate ((x^(a))/(x^(b)))^(a+b)*((x^(b))/(x^(c)))^(b+c)*((x^(c))/(x^(a)))^(c+a) with respect to x.

Assuming that x is a positive real number and a ,\ b ,\ c are rational numbers, show that: ((x^a)/(x^b))^(1/(a b))\ ((x^b)/(x^c))^(1/(b c))\ \ ((x^c)/(x^a))^(1/(a c))=1

Prove that :((x^(a))/(x^(b)))^(a+b-c)((x^(b))/(x^(c)))^(b+c-a)((x^(c))/(x^(a)))^(c+a-b)=1