Enthalpy of neutralization of `HCl` by `NaOH` is `-57.1 J//mol` and by `NH_(4)OH` is `-51.1 KJ//mol`. Calculate the enthalpy of dissociation of `NH_(4)OH`.

If enthalpy of neutralisation of HCl by NaOH is -57 kJ " mol"^(-1) and with NH_(4)OH is -50 kJ " mol"^(-1) . Calculate enthalpy of ionisation of NH_(4)OH (aq).

If enthalpy of neutralisation of HCl by NaOH is -57 kJ " mol"^(-1) and with NH_(4)OH is -50 kJ " mol"^(-1) . Calculate enthalpy of ionisation of NH_(4)OH (aq).

If enthalpy of neutralisation of HCl by NaOH is -57 kJ " mol"^(-1) and with NH_(4)OH is -50 kJ " mol"^(-1) . Calculate enthalpy of ionisation of NH_(4)OH (aq).

Enthalpy of neutralization of HCl by NaOH is -55.84 kJ/mol and by NH_(4)OH is -51.34 kJ/mol. The enthalpy of ionization of NH_(4)OH is :

Enthalpy of neutralization of HCl by NaOH is -55.84 kJ/mol and by NH_(4)OH is 51.34 kJ/mol. The enthalpy of ionization of NH_(4)OH is :

Enthalpy of neutralization of HCl by NaOH is -55.84 kJ/mol and by NH_(4)OH is 51.34 kJ/mol. The enthalpy of ionization of NH_(4)OH is :

If enthalpy of neutralisation of HCl by NaOH is -58.84 kJ/mol and by NH_4OH is -52.26 kJ/mol, then enthalpy of ionisation of NH_4OH is

The enthalpy of neutralisation of HCl by NaOH is -57.1 KJ and that of HCN by NaOH is -12.1 KJ mol^(-1) the enthalpy of ionization of HCN is

The enthalpy of neutralization of NH_(4)OH and CH_(3)COOH is – 10.5 kcal/mole and enthalpy of neutralization of strong base and CH_(3)COOH is – 12.5 kcal/mole. Calculate the enthalpy of dissociation of NH_(4) OH -