Find free electrons per unit volume in a wire of density `10^(4)kg//m^(3)`, atomic mass number 100 and number of free electron per atom is one.

There is a current of 40 ampere in a wire of 10^(-6)m^(2) are of cross-section. If the number of free electron per m^(3) is 10^(29) then the drift velocity will be

There is a current of 40 ampere in a wire of 10^(-6)m^(2) are of cross-section. If the number of free electron per m^(3) is 10^(29) then the drift velocity will be

There is a current of 40 ampere in a wire of 10^(-6)m^(2) are of cross-section. If the number of free electron per m^(3) is 10^(29) then the drift velocity will be

How many number of free electrons present on each carbon atoms in graphite

We know that copper is a conductor of electricity due to presence of free electrons in it. Assume that on an average each copper atom provides one free electron. Find the number of free electrons per unit valume of copper. The density of copper is approximately 9,000 kg / m^3 and its atomic mass is 63.5 u.

An electric current of 16 A exists in a metal wire of cross section 10^(-6) m^(2) and length 1 m. Assuming one free electron per atom. The drift speed of the free electrons in the wire will be (Density of metal = 5 xx 10^(3) kg//m^(3) atomic weight = 60)

An electric current of 16 A exists in a metal wire of cross section 10^(-6) m^(2) and length 1 m. Assuming one free electron per atom. The drift speed of the free electrons in the wire will be (Density of metal = 5 xx 10^(3) kg//m^(3) atomic weight = 60)