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The length of the common chord of the tw...

The length of the common chord of the two circles `x^2+y^2-4y=0` and `x^2+y^2-8x-4y+11=0` is

Text Solution

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`x^2+(y-2)^2=4 -(1)`
`(x-4)^2+(y-2)^2=9 -(2)`
from diagram
`CC_1=4`
area of `/_ACC_1=sqrt((9/2)*(5/2)*(3/2)*(1/2))`
=`sqrt(135)/4`
area can also be find by=`1/2*AD*CC_1`
so, it can be said that
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