A slit of worth `12 times 10^-7` m is illuminated by light of wavelength 6000A. The angular width of the central maximum is approximately-

Fraunhofer diffraction from a single slit of width 1.24 xx 10^(-6)m is observed with the light of wavelength 6200 Å. Calculate the angular width of the central maximum.

In a single slit diffraction pattern the angular width of a central maxima is 30^(@) . When the slit is illuminated by light of wavelength 6000Å . Then width of the slit will be approximately given as :

A slit of size 0.15m is placed at 2.1m from a screen. On illuminated it by a light of wavelength 5xx10^-5cm . The width of central maxima will be

A slit of size 0.15m is placed at 2.1m from a screen. On illuminated it by a light of wavelength 5xx10^-5cm . The width of central maxima will be

In single slit diffraction of light of wavelength lambda , angular width of the central maximum (considering slit width d) will be

A slit of width 'a' is illuminated by a light of wavelength 6000Å . For what value of 'a' will be first maximum fall at an angle of diffraction of 30° ?

In a Young's double slit experiment,two slits are 1.5 mm apart and a screen in placed at a distance 1.2 m from the plane of the slits .The slits are illuminated with light of wavelength 6,000 overset @A .Find the inimum distance from the central maximum for which the intensity is half of the maximum intensity.