The total energy of an electron in second excited state of hydrogen atom is -1.51eV. Calculate (i) KE of electron (ii) PE of electron in this state.

The total energy of an electron in the second excited state fo hydrogen atom is -1.51 eV .Calculate the potential energy of the electron in this state.

The energy of an electron in an excited state of hydrogen atom is -1.51 eV . Calculate the angular momentum of the electron in this state. h = 6.63 xx 10^-34 Js

The total energy of an electron in the first excited state of hydrogen atom is -3.4 eV . What is the potential energy of the electron in this state ?

The total energy of an electron in the first excited state of hydrogen atom is -3.4eV. What is the kinetic energy of the electron in this state ?

The total energy of an electron in the first excited state of the hydrogen atom is -3.4eV. What is the potential energy of the electron in this state ?

(a) The radius of the innermost electron orbit of a hydrogen atom is 5.3 xx 10^(-11) m. Calculate its radius in n =2 orbit. (b) The total energy of an electron in the second excited state of the hydrogen atom is -1.51 eV. Find out its (i) kinetic energy and (ii) potential energy in this state.

The total energy of an electron in the first excited state of the hydrogen atom is about-3.4ev What is the kinetic energy of the electron in this state?

Total energy of electron in an excited state of hydrogen atom is -3.4 eV . The kinetic and potential energy of electron in this state.